What is the theoretical yield of CuO?

Question

What is the theoretical yield of CuO?

 

-Experimental yield of Copper II oxide-1.4

-Equation-CuCO3^.Cu(OH)₂ -->CuO + CO₂+H₂O

Answer 1

the balanced chemical equation that we're starting with here is

CuCO3​ ⋅ Cu(OH)2​ → CO2 ​ + H2​O + 2CuO

meaning that the mole ratio is 1 mole CuCO3: 2 moles of CuO

next then i would determine the moles of CuCO3 by dividing the given mass by the molar mass

Moles = 1.01 g / 221.114 g/mol = 0.004568 mol CuCO3

using the mole ratio that becomes

Moles of CuO = 0.004568 mol CuCO3 x 2 mol CuO / 1 mol CuCO3 = 0.009136 mol CuO

the last step then is multiplying that value by the molar mass

0.009136 mol CuO x 79.545 g/mol = 0.727 g

meaning that you end up producing approximately 0.727 grams of CuO for the theoretical yield in this scenario

Answer 2

Hi Kelani

 

To find the theoretical yield of CuO you first need to calculate the mass of copper II oxide. To do this you need to know that mass of CuCO3(OH)2 which isn't provided in your question. Please give the mass of the reactant before I can answer your question.