you can approach this as a Combination problem because the order in which you pick them out does not matter
C(6, 2) = 6! / 2!(6 - 2)! = 15
meaning that there are 15 different ways that you could pick 2 items out of 6
you can approach this as a Combination problem because the order in which you pick them out does not matter
C(6, 2) = 6! / 2!(6 - 2)! = 15
meaning that there are 15 different ways that you could pick 2 items out of 6
Alan G. answered 03/08/16
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