joe and ahmad had 80 marbles altogether.Ahmad has 4 times as many marbles as Joe.how many marbles each boy have?

Question

its a maths question...i need all the working..

Answer 1

Hello, thank you for taking the time to post your question!

The key to solving a question like this is accurately putting together a system of equations to represent the situation. For this one we have

J + A = 80   because there are 80 marbles total

A = 4J          since Ahmad has 4 times as many marbles as Joe

If you substitute the second part back into the first equation it becomes

J + 4J = 80

Then solve for J:

5J = 80

J = 16

Meaning that

A = 4 x 16 = 64

What that means is that Joe has 16 marbles and Ahmad has 64 marbles.

I hope that helps get you moving in the right direction! Feel free to reach out if you have any additional questions beyond that :)

Answer 2

 

Joe and Ahmad had 80 marbles altogether.  Ahmad has 4 times as many marbles as Joe. How many marbles each boy have?

 

Let m= the number of marbles Joe has

Let 4m=the number of marbles Ahmad has

 

    m + 4m = 80

          5m = 80

            m=16

 

           4m=4(16)=64                       Check:   16+64=80 checks

 

ANSWER:  Joe has 16 marbles and Ahmad has 64 marbles.

 

Hope this helps you understand the process.

THINK MATH!!