
David W. answered 02/22/16
Tutor
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Experienced Prof
The expression:
1-r^2
is the difference of two squares: 1^2 and r^2.
While it is true that (1+r)(1-r) produces (1-r^2)
it is also true that (-1-r)(r-1) produces (1-r^2)
Now, are those factors really the same or are they unique? We might have to test a value of r to assure ourselves. Let's try:
r = 1/4
(1-r^2) = (1+r)(1-r)
(1-(1/4)^2) = (1+(1/4))(1-(1/4))
(1- (1/16)) = (5/4)(3/4)
15/16 = 15/16
(1-r^2) = (-1-r)(r-1)
(1-(1/4)^2) = (-1-(1/4))((1/4)-1)
(1-(1/16)) = (-5/4)(-3/4)
15/16 = 15/16
So, the value (15/16) has two sets of factors:
(5/4) and (3/4)
or
(-5/4) and (-3/4)
There is a HUGE difference when the problem asks you to factor:
1-r^2 = 0
because 0 is neither positive nor negative and we must set either:
1-r = 0
or
1+r = 0
because this problem states that the product is 0 and because the Multiplicative Property of Zero requires that one of the factors equals 0. Thus either r=1 or r=-1. [note: other values of a and b are not important if SQRT(a)=±SQRT(b)].
So, if the problem is an equation (set equal to 0), factor it the usual way; if the problem is an expression, factor it differently.
Let's check this by doing the example problem again:
Solve: 1 - r^2 = 15/16
-r^2 = 15/16 - 1
-r^2 = -1/16
r^2 = 1/26
r = ±1/4, then answer, what is (1-r) and (1+r)? Are there two sets of answers?
1 - r^2 = 0
-r^2 = -1
r^2 = 1
r = ±1 then answer, what is (1-r) and (1+r)? Are there two sets of answers?

Justin R.
1-r2
is the difference of two squares: 12 and r2.
While it is true that (1+r)(1-r) produces (1-r2)
it is also true that (-1-r)(r-1) produces (1-r2)
Now, are those factors really the same or are they unique? We might have to test a value of r to assure ourselves. Let's try:
r = 1/4
(1-r2) = (1+r)(1-r)
(1-(1/4)2) = (1+(1/4))(1-(1/4))
(1- (1/16)) = (5/4)(3/4)
15/16 = 15/16
(1-r2) = (-1-r)(r-1)
(1-(1/4)2) = (-1-(1/4))((1/4)-1)
(1-(1/16)) = (-5/4)(-3/4)
15/16 = 15/16
So, the value (15/16) has two sets of factors:
(5/4) and (3/4)
or
(-5/4) and (-3/4)
There is a HUGE difference when the problem asks you to factor:
1-r2 = 0
because 0 is neither positive nor negative and we must set either:
1-r = 0
or
1+r = 0
because this problem states that the product is 0 and because the Multiplicative Property of Zero requires that one of the factors equals 0. Thus either r=1 or r=-1. [note: other values of a and b are not important if √(a)=±√(b)].
So, if the problem is an equation (set equal to 0), factor it the usual way; if the problem is an expression, factor it differently.
Let's check this by doing the example problem again:
Solve: 1 - r2 = 15/16
-r2 = 15/16 - 1
-r2 = -1/16
r2 = 1/26
r = ±1/4, then answer, what is (1-r) and (1+r)? Are there two sets of answers?
1 - r2 = 0
-r2 = -1
r2 = 1
r = ±1 then answer, what is (1-r) and (1+r)? Are there two sets of answers?
02/22/16