
David W. answered 02/10/16
Tutor
4.7
(90)
Experienced Prof
Let:
L = length of rectangle
W = width of rectangle
Translate:
"perimeter of a rectangle is 220 feet" means
2L + 2W = 220 [note: P = 2L+2W]
"area of the rectangle is not Let:
L = length of rectangle
W = width of rectangle
Translate:
"perimeter of a rectangle is 220 feet" means
2L + 2W = 220 [note: P = 2L+2W]
"area of the rectangle is not to exceed 1425 square feet" means
LW ≤ 1425 [note: A=LW]
{note: "not to exceed" is "not greater than"; that is, "less than or equal to"]
Re-write:
2L + 2W = 220
L + W = 110 [divide both sides by 2]
W = 110 - L [solve for W so we can get rid of it]
LW ≤ 1425
L(110-L) ≤ 1425
110L - L2 ≤ 1425
L2 - 110L ≥ -1425 [multiply by (-1) reverses sense of inequality]
L2 - 110L + 1425 ≥ 0 [add +1425 to both sides retains sense of inequality]
(L - 15)(L - 95) ≥ 0 [either factor or use quadratic formula]
[note: this is true when terms are ++ or -- or 00; that is, L≥95 or L≤15]
So,
The length must be greater than or equal to 95 or less than or equal to 15.
Since the perimeter is fixed at 220, if the length is greater than or equal to 95, then it must also be less than 110 (for there to be any width at all).
Since the perimeter is fixed at 220, if the length is less than or equal to 15, then it must also be greater than 0.
The expression is: 0< L ≤15 OR 95 ≤ L < 110
L = length of rectangle
W = width of rectangle
Translate:
"perimeter of a rectangle is 220 feet" means
2L + 2W = 220 [note: P = 2L+2W]
"area of the rectangle is not to exceed 1425 square feet" means
LW ≤ 1425 [note: A=LW]
{note: "not to exceed" is "not greater than"; that is, "less than or equal to"]
Re-write:
2L + 2W = 220
L + W = 110 [divide both sides by 2]
W = 110 - L [solve for W so we can get rid of it]
LW ≤ 1425
L(110-L) ≤ 1425
110L - L2 ≤ 1425
L2 - 110L ≥ -1425 [multiply by (-1) reverses sense of inequality]
L2 - 110L + 1425 ≥ 0 [add +1425 to both sides retains sense of inequality]
(L - 15)(L - 95) ≥ 0 [either factor or use quadratic formula]
[note: this is true when terms are ++ or -- or 00; that is, L≥95 or L≤15]
So,
The length must be greater than or equal to 95 or less than or equal to 15.
Since the perimeter is fixed at 220, if the length is greater than or equal to 95, then it must also be less than 110 (for there to be any width at all).
Since the perimeter is fixed at 220, if the length is less than or equal to 15, then it must also be greater than 0.
The expression is: 0< L ≤15 OR 95 ≤ L < 110