An airport parking lot is a rectangle 1 7/10 of a mile wide and 2 3/4 of a mile long. How much fencing is needed to enclose the lot?

Question

An airport parking lot is a rectangle1 7/10 of a mile wide and 2 3/4  of a mile long.  How much fencing is needed to enclose the lot?  Show work using fraction arithmetic, and include units with your answer.

Answer 1

perimeter = 2(length + width)

perimeter = 2(1 7/10 m + 2 3/4 m)

perimeter = 2(1 14/20 m + 2 15/20 m)    LCD

perimeter = 2(3 29/20 m)                         add

perimeter = 2(4 19/20 m)                         proper fraction

perimeter = 8 38/20 m                             multiply

perimeter = 9 18/20 m                             proper fraction

perimeter = 9 9/10 m                               reduce

 

The fence is 9 9/10 mile long.