I don't know how to do this. I need to find the equation of the line that passes through (13,19) & (16,13)

Hi Idk,

The equation is found first by measuring the slope of the line.

Slope is denoted by rise over run (rise/run), or y/x.

This is found by taking (y2-y1)/(x2-x1)

in the points given, x is the first value and y is the second, so x1=13, x2=16, y1=19 and y2=13.

Therefore, rise over run (slope)=

(13-19)/(16-13) = (-6/3) = -2

Furthermore, the equation of a straight line is always in the form y=mx+b, where m is the slope and b is the y-intercept (or where x=0). You can find b by plugging in either of the two points you are given in the equation

i.e. 13=(-2)(16)+b

13= -32 +b

b= 13+32

b= 45

So the equation of the line (in y=mx+b format) is

**y= (-2)x + 45**

*You can verify that this equation is correct by plugging in x or y from the other set of values into the equation:*

*y= -2x + 45*

*y= -2(13) +45*

*y= -26 + 45*

*y=19*

*Hope this helps!*

*Jason*