Which is a zero of the quadratic function f(x) = 16x2 + 32x - 9?

Question

x = –5.25

x = –2.25
x = –1.25
x = –0.25

Answer 1

f(x) = 16x² + 32x - 9

 

To find the "zeros", set f(x) = 0:

 

     0 = 16x² + 32x - 9

 

The equation is solvable by factoring or by using the quadratic formula.  The factors (use the "ac" method) are:

 

     0 = (4x-1)(4x+9)

 

     x = 1/4 = 0.25 and x = -9/4 = -2.25