Frank P. answered • 01/16/16
Tutor
New to Wyzant
Math Tutor for the Grand Junction area
Use the distance equation to find the distance of the diameter.
d2 = (xf-xi)2 + (yf-yi)2 +(zf-zi)2
d2 = (-6-0)2+(4-0)2+(0-6)2
d2=36+16+36=88
d2 = (xf-xi)2 + (yf-yi)2 +(zf-zi)2
d2 = (-6-0)2+(4-0)2+(0-6)2
d2=36+16+36=88
d=sqrt(88)
Radius is half the diameter
r=d/2
r=sqrt(88)/2
To find the middle of the diameter use the center equation
(xf-xi)/2, (yf-yi)/2, (zf-zi)/2
(-6-0)/2, (4-0)/2, (0-6)/2
(-3,2,-3) Center
Now use the equation for a sphere
(x-xc)2+(y-yc)2+(z-zc)2=r2
(x+3)2+(y-2)2+(z-3)2=(sqrt(88)/2)2
(x+3)2+(y-2)2+(z-3)2=88/4
(x+3)2+(y-2)2+(z-3)2=22
