The sum of 5 consecutive even numbers is 460

Question

The sum of 5 consecutive even numbers is 460

Answer 1

Let n be the first of the numbers.  Then the second number is n+2 and the third is n+4 and so on.  So we have 460 = n + (n+2) + (n+4) + (n+6) + (n+8)  = 5n + 20.  So subtracting 20 from both sides, we have 440 = 5n.  Dividing both sids by 5, we get n = 88.  So the numbers are 88, 90, 92, 94, and 96.