I need help on understanding how to find the solution. All answers will be helpful and I appreciate all of you for your explanations.

Hi Jason;

*(-3, -3), perpendicular to y-7/3x+3.*

I am assuming that the equation is...

y=(7/3)x+3

If not, please let me know.

The slope of this line is 7/3.

The slope of the line perpendicular to this is the negative inverse; -3/7.

y=(-3/7)x+b is a formula written in slope-intercept form.

You need point-slope, especially since the y-intercept, value of b, is still unknown.

y-y

_{1}=m(x-x_{1})y--3=(-3/7)(x--3)

Subtracting a negative is the same as adding a positive.

y+3=(-3/7)(x+3)

Let's distribute...

y+3=(-3/7)(x)-(9/7)

Let's subtract 3 from both sides as we proceed to isolate y...

-3+y+3=(-3/7)x-(9/7)-3

y=(-3/7)x-(9/7)-3

Considering the fact that 3=21/7...

y=(-3/7)x-(9/7)-(21/7)

y=(-3/7)x-(30/7)