describe and correct the error

Question

t^2-5t=7 discriminant = (-5)^2-4(1)(7)=25-28=-3 discriminant is negative, so there are no real solutions.

Answer 1

The discriminant of Ax²+Bx+C = 0 is B²-4AC.

 

For t²-5t = 7, t²-5t-7 = 0

 

Discriminant = (-5)² - 4(1)(-7) = 25 + 28 = 53 > 0

 

Since the discriminant is positive, the equation has two real solutions.  

 

                   

Answer 2

If you calculate the discriminant yourself you should be able to easily describe and correct the error