nCr = n!/[(r!)(n-r)!] = "n choose r"
So, 12C5 = 12!/[(5)!(7!]
= (12)(11)(10)...(3)(2)(1)
--------------------------------- = 792
(5)(4)(3)(2)(1)(7)(6)(5)....1
Kimberly L.
asked 01/08/16
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