
Hamilton A. answered 01/01/16
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Degrees in Math, 10+ Years Tutoring
In set theory, given sets X and Y, we say that (X ⊆ Y) if and only if, for every element x ∈ X, it's also the case that x ∈ Y. X is said to be a subset of Y.
In general, to prove that X ⊆ Y for any sets X and Y, the strategy is usually to consider an arbitrary element x ∈ X, and then use properties of x or X and valid reasoning to prove that x must also be in Y.
For example, to prove that (A ∪ C) ⊆ (B ∪ D), we consider an arbitrary x in (A ∪ C), and then try to show that x must also be in (B ∪ D). If x is in (A ∪ C), then either x ∈ A or x ∈ C (or both, but we just need these two cases.) Considering these two cases:
- If x ∈ A, then x ∈ B, by definition of A ⊆ B
- If x ∈ C, then x ∈ D, by definition of C ⊆ D
At least one of these cases must be true, so x ∈ B or x ∈ D. And therefore x ∈ (B ∪ D), as desired.
You should be able to adapt this argument to the second case. Good luck!