Raymond B. answered • 08/03/21
Tutor
5
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Math, microeconomics or criminal justice
x^3 - 1 = (x-1)(x^2+x +1)
x^3+4 has no integer factors and only one real factor
x^3 =-4
x = -4^(1/3) so x+4^(1/3) could be one irrational factor
there are 3 cube roots, but the other two are imaginary
Two imaginary and one irrational factor is the only possibilities.
(x^3-1)/(x^3+4) = (x-1)(x^2+x+1)/(x^3+4)
