f(t) = (t4-9)1/6
f(t) is defined as long as t4-9 ≥ 0
t4-9 = (t2-3)(t2+3)
t4-9 = 0 when t = ±√3
When t ≤ -√3, t4-9 ≥ 0
When t is between -√3 and √3, t4 - 9 < 0
When t ≥ √3, t4-9 ≥ 0
Domain of f(t): (-∞, -√3] ∪ [√3, ∞)

Kristi D.
asked 12/27/15Mark M. answered 12/27/15
Mathematics Teacher - NCLB Highly Qualified
Kristi D.
12/27/15
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Mark M.
12/28/15