Arthur D. answered 12/22/15
Tutor
4.9
(306)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
distance=rate*time
distances are the same
(20+c)(1/2)=(20-c)(2/3)
multiply both sides by 6
3(20+c)=4(20-c)
60+3c=80-4c
3c+4c=80-60
7c=20
c=20/7
c=2 6/7 mph is the speed of the current
check: (22 6/7)(1/2)=(17 1/7)(2/3)
(160/7)(1/2)=(120/7)(2/3)
(80/7)=(80/7) (80/7=11 3/7 miles is the distance traveled)