Please help solve: Using the equation s=n(nxn) +1)\ 2, where s stands for sum, find the sume of each row and column in a 4x4 normal magic square?

Question

The equation is as follows:  s= n(n² +1) , where s stands for sum.  Find the sum of each row and column in a 4x4

                                                  2

 

normal magic square. 

 

Thank You!

Answer 1

So n=4

 

S =[ 4 ( 4*4 + 1)]  /2  = 4 ( 17) /2 = 34.