i need help with this problem :-6a^4+4a^3-2a^2

I'm with Edwin - you can't **solve** an expression. You need an equals sign in the mix (i.e. an equation). If we have an expression (algebra stuff without an equals sign) we can only **simplify**.

A good starting place would be to factor. The number coefficients all share a greatest common factor of 2 (do you see how 2 goes into 2, 4, and 6?) and for the variables the greatest common factor is a^2 (a^2 goes into a^2, a^3, and a^4... don't forget exponents are just a handy way of writing multiplication!)

so if I pull a 2a^2 out of each term, the first term becomes -3a^2, the second term becomes 2a, and the third term becomes -1:

2a^2(-3a^2 + 2a - 1)

Can we factor the trinomial in parentheses?

Not.. really. I know this because I can look at the discriminant (b^2 - 4ac.. the thing under the square root in the quadratic formula?) and it is negative. So we're done, since -3a^2 + 2a - 1 doesn't have real roots, so we can't factor it further.

I hope this helps you get started - please check back in if you need more!

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