Tymon E. answered 10/28/13
Tutor
5
(8)
Passionate, bilingual tutor for MS/HS Science, Math, & Spanish
The firs thing you need to do in this type of problem is factor it. First, I look at the leading coefficient of x^2. As there is no coefficient given, you can leave it as x:
(x )(x )
I then look at the last number (in this case a -4) The two factors of -4 are +/- 2 and 4 and 1.
(x-2)(x+2) or (x-4)(x+1) or (x-1)(x+4)
If I were to FOIL these though, I would find that I could not get a positive 6x. At this point I would use the quadratic formula:
x= - b +/- (√(b2-4ac)/2a
x = (-6 + √(62-4(1)(-4))/2(1) and x = -6 - √(62-4(1)(-4))/2(1)
x = -6 + √(36-(-16))/2 and x = -6 - √(52)/2
x = -6 + √(52)/2 and x = -6 - √(52)/2
√(52) -> √13 * √4 -> 2√13
x = (-6 + 2√13)/2 and x = (-6 - 2√13)/2
x = -3 + √13 and x = -3 - √13 (Exact Answers)
x = .61 and x = -6.6 (Decimal Answers)