
Doug C. answered 12/11/15
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Math Tutor with Reputation to make difficult concepts understandable
Let L = Leah's marble count; D = Dan's marble count
L = D + 28
and
1/3 L = 4/5 D
At this point you have a choice of how to proceed. Let's replace L in the 2nd equation with D + 28.
1/3 (D + 28) = 4/5 D
Multiply both sides by 15 to eliminate the fractions.
5(D+28) = 12D
5D + 140 = 12D
7D = 140
D = 20; L is 28 more than 20, so L=48.
Note: if you have not reached the point where you are using two equations for problems like this then you might start this way.
L = Leah's marble count.
L-28 = Dan's marble count.
1/3 L = 4/5(L-28)
5L = 12(L-28)
etc.