Mark M. answered 12/10/15
Tutor
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Mathematics Teacher - NCLB Highly Qualified
An inequality containing an absolute value must be solved twice.
Once assuming the argument is positive, and once assuming the argument is negative
I.
Assume 4 - 2x is positive
|4 - 2x| > 2
4 - 2x > 2 subtract 4 from both sides
-2x > -2 divide both sides by -2 (order changes!)
x < 1
II.
Assume 4 - 2x is negative
|4 - 2x| > 2
-(4 - 2x) > 2 distribute
-4 + 2x > 2 add 4 to both sides
2x > 6 divide both sides by 2
x > 3