Youngkwon C. answered 11/30/15
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Knowledgeable and patient tutor with a Ph.D. in Electrical Eng.
Hi Mia,
If the problem is to find limx→∞{√(x2+ax) - √(x2+bx)},
then we can slove it as follows.
limx→∞{√(x2+ax) - √(x2+bx)}
= limx→∞{√(x2+ax) - √(x2+bx)}·{√(x2+ax) + √(x2+bx)}/{√(x2+ax) + √(x2+bx)}
= limx→∞{(x2+ax) - (x2+bx)}/{√(x2+ax) + √(x2+bx)}
= limx→∞(a-b)x/{√(x2+ax) + √(x2+bx)}
= limx→∞(a-b)/{√(1+a/x) + √(1+b/x)} (both numerator & denominator divided by x)
= (a - b)/2