Hi Lody, this problem is an application of the D(istance) = R(ate) * T(ime) equation. We need to solve the equation for time. Let x be the speed of the current.
Equation downstream:
Dd = Rd * Td
Solving for time:
Td = Dd / Rd
Td =12 / (15 + x)
Equation upstream:
Du = Ru * Tu
Solving for time:
Tu = Du / Ru
Tu =12 / (15 - x)
Solve:
We know the total time of the round trip is 1 hour and 40 minutes, or 1.67 hours.
That means:
Td + Tu = 1.67
Substituting for Td and Tu gives:
12 / (15 + x) + 12 / (15 - x) = 1.67
Find common denominator on the left side:
The common denominator is (15 + x) * (15 - x)
(12 * (15 - x) + 12 * (15 + x)) / ((15 + x) * (15 - x)) = 1.67
Multiply both sides by the common denominator:
12 * (15 - x) + 12 * (15 + x) = 1.67 * ((15 + x) * (15 - x))
Clear parenthesis:
180 - 15x + 180 + 15x = 1.67 * (225 - 15x + 15x - x2)
360 = 1.67 * (225 - x2)
Divide both sides by 1.67:
360 / 1.67 = 225 - x2
Multiply the equation by -1:
-360 / 1.67 = -225 + x2
Add 225 to both sides and rearrange:
x2 = 225 - 360 / 1.67
x2 = 9.43
Find the square root of x:
x = ±3.07
The solutions are x = 3.07 and x = -3.07. We can discard x = -3.07 because water normally does not run back up stream. That means the stream is flowing at a rate of 3.07 kmp.
Check:
12 / (15 + 3.07) + 12 / (15 - 3.07) = 1.67
12 / 18.07 + 12 / 11.97 = 1.67
.66 + 1.01 = 1.67
1.67 = 1.67, values check.
Questions?