Omari S. answered 11/24/15
Tutor
New to Wyzant
Johns Hopkins Grad Student and MCPS Math Teacher w/ Eng. Background
Use the combination rule of n!/k!(n-k)! where n is the number of options (7) and k is the number of slots (2).
Do this if the order does not matter.
7!/2!(7-2)! = 7*6*5*4*3*2*1/2*1*(5*4*3*2*1) = 7*6/2 = 21
If, however, the order does matter, then use the permutation rule of n!/(n-k!) with n = 7 and k =2 giving 7*6 = 42.