Hi,
I assume you are taking Calculus. Ok so let's get started:
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Let the length of the big rectangle be equal to X, and the width of the big rectangle equal to y
then : X+X+y+y+y+y = 2000
so 2x+4y=2000 which means x+2y =1000
Now,
Area of the big rectangle is: A = X.Y
but we know from the previous equation (which we found using the perimeter) that x= 1000-2y
so substitute that into the area equation so we deal with only one variable:
A(y) = (1000-2y)*(y) = 1000y - (2*(y^2))
Now we just simply take the derivative, set it equal to 0, to find the max value.
A'(y) = 1000 -4y
A'(y) =0 =====> 4y=1000 ===> y=250
so plug this value back for y and find x:
x=1000- 2y = 1000-500 = 500
so when x=500 and y = 250, the area will be maximized. and the area of the large rectangle would be: 500*250 = 125000