
Nina K. answered 11/16/15
Tutor
New to Wyzant
Physics, math and language tutor with 20+ years of experience
What you need to do is use KE = mv2/2 formula. In the beginning, both balls are moving with a speed of v, so total KE for the system is 2mv2/2 for the heavy one and mv2/2 for the light one, which gives you 3mv2/2 for the system in total.
After the balls collide, you'll have their common speed as ... I am not sure you found it correctly, by the way. With conservation of momentum, 2mvi - mvi = (2m+m)vf, which means mvi = 3mvf, making vf = vi/3, only 1/3 of the original speed.
So, the KE of the system after the collision is 3m*(v/3)2/2.
Once you square, you get mv2/6
So, you went from KEi = 3mv2/2 to KEf = mv2/6
Common denominator will give you 9mv2/6 for initial energy, then your change in KE is 8mv2/6.
If you are looking for the % of the change, you divide the change by the original
(4/3)/(3/2)=8/9 = 89% of energy was lost.
You can check with numbers if it helps:
let's say you have two balls: 1kg and 2 kg. The heavier is moving with a +5 m/s, the light - with - 5m/s
After they collide, their speed is 5/3 m/s.
You can check: 2*5 - 1*5 = (2+1) v, which gives you v = 5/3
Then let's find KE for each ball: 2 kg KE = 2*25/2 = 25 J, 1 kg KE = 1*25/2 = 12.5 J. Total energy is 37.5 J
After the collision, KE = (2+1)*(5/3)2/2 = 3*25/18=25/6 .
How much energy was lost? 37.5 - 25/6 = (225-25)/6 = 200/6 J.
What is that in relation to the original energy? (200/6)/37.5 = 0.89 = 89%