
Anthony B. answered 11/10/15
Tutor
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Experienced Calculus Tutor
1. the angle of elevation formed by the ground and the bottom of the antenna is 62.6°
2. the side opposite to this angle is 1000
3. to find the distance from the building to the point of observation, we do: tan(62.6°) = 1000/a
4. a = 1000/tan(62.6°) ≈ 518.351
5. the angle of elevation formed by the ground and the top of the antenna is 65.8°
6. the side opposite to this angle is 1000 + the height of the antenna
7. to find this combined height, we do: tan(65.8°) = o/518.351
8. o = 518.351*tan(65.8°) ≈ 1153.383
9. now, let y = the height of the antenna
10. therefore, the height of the building + the height of the antenna = 1000 + y = 1153.383
11. subtract 1000 from both sides: y = 153.383
12. thus, the height of the antenna is approx. 153 ft