Al K. answered 11/05/15
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4.5
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25 years of teaching algebra and calculus
sec x = 1/cos x
csc x = 1/sin x
Therefore
sec x/csc x + sinx /cosx = (1/cos )/(1/sin x) + six /cos x =tan x + tanx = 2 tan x
csc x = 1/sin x
Therefore
sec x/csc x + sinx /cosx = (1/cos )/(1/sin x) + six /cos x =tan x + tanx = 2 tan x