F
A______B______E
C______D
F
A______B______E
C______D
How do we know which square is larger? ACEF (because its diagonal AE is longer than its side AC, which happens to be the diagonal of ABCD). Comparing the large square to the small square the ratio of similarity is √2, so the ratios of the areas is √2 squared, 2. So the larger square has twice the area of the small square.
I'm going to do this based on the way I think your drawing should've looked (as it is now, ACEF does not make a square...). It seems like it should look like this, based on your tag about congruent triangles.
F
A B E
D C
If you draw this on paper, you'll see it breaks up into 5 congruent triangles. The
area of square ABCD is twice the area of triangle ABC, and the area of triangle ACEF is four times the area of triangle ABC. Area of a triangle is half the base times the height.
The area of triangle ABC: 0.5*AB*BC
Area of square ABCD: 2*0.5*AB*BC but we know AB=BC as it's a square. So Area of square ABCD = 2*0.5*AB*AB = AB^2
AB = 1/2*AE, and the area of ACEF is twice the area of triangle ACE.
Area of triangle ACE = 0.5*AE*BC, but BC=AB and AE = 2*AB, so area of ACE = 0.5*2*AB*AB = AB^2
Area of square ACEF = 2*AB^2 which is twice the area of ABCD, so the area of ABCD is half the area of ACEF.
Statement Reason
ABCD is a square Given
AECF is a square Given
AB = (1/2)AE Given
Area ABCD = AB·AC Def. of area of a square
Area AECF = AE·AC Def. of area of a square
Area ABCD = [(1/2)AE]·AC Substitution
Area of ABCD = (1/2) AE·AC Substitution
Comments
You could also prove it using pythagoras theorem and the fact that the area of a square is equal to the side length squared.
Area of ABCD = AB^2
You could also write the area of ABCD as (using AB = 0.5*AE thus AE = 2*AB): (0.5*AE)^2 = (0.5*2*AB)^2 = AB^2
Area of ACEF = AC^2
Use pythag to find length of AC: AC^2 = AB^2+BC^2 = AB^2+AB^2 = 2*AB^2
Note that the area of ACEF = AC^2 = 2*AB^2 = 2*(area of ABCD) so the area of ABCD is half that of ACEF.