y=3x-5 (-2,5)

Question

 i need help with line passing through the pont and parallel line

Answer 1

Hi Aden;

y=3x-5 (-2,5)

I am assuming that the (-2,5) point is NOT part of this line for which you present the equation.

The reason for my assumption is...

5≠3(-2)-5

5≠-6-5=-11

 

Therefore, the coordinate provided is part of the parallel line you must find the equation for.

Is this correct?  If yes, please see below.  If not, please ask again or comment below.

y=3x-5 (-2,5)

For the two to be parallel to each other, these must have the same slope.  Therefore...

y=3x+b

To find b, the y-intercept, we will plug-in the coordinate provided...

5=3(-2)+b

5=-5+b

We will add 5 to both sides...

5+5=-5+b+5

10=b

The parallel equation is...

y=3x+10