whats the slope-intercept for (0,4) (-3,0)

Question

i need help finding the slope-intercept for (0,4) (-3,0)

Answer 1

1. Slope-intercept form of linear equation is
 y = mx + b
2. The rational way to solve the given problem is to use the intercept form of a linear equation.
    x       y  
  —  +  —  =  1 
   a        b        
(where (a , 0) are coordinates of the x-intercept
and (0, b) are coordinates of the y-intercept )
~~~~~~~~~~~
(-3, 0) ---> a = -3
(0, 4) ----> b = 4
    x        y   
 —— + —— = 1
  -3         4
Let's multiply our equation by 12:
         x                y   
12 • —— + 12 • —— = 12 • 1
        -3               4 

 - 4x + 3y = 12
+ 4x         + 4x

  3y  =  4x  +  12
 ÷3     ÷3      ÷3
         4
y  =  —  x  +  4 
         3  

Answer 2

First you must know that the slope intercept form is y=mx+b where m is the slope (or rise over run) and b is the y-intercept. 

(0,4) and (-3,0) are coordinates for x and y. So first we can already note that the y-intercept (what y equals when x is 0) is 4. So b = 4. 

Next we must find the slope, m. Slope is rise over run; or the change of y over the change of x. Let me show you with this problem. We have two x variables and two y variables. X is 0 and -3 and Y is 4 and 0. 

4 - 0 =   4

0 - -3 = +3

Okay so on top we have the change of y (4-0) and on bottom is the change in x (0--3) which becomes (0+3) because of the two negative signs. So the slope is positive 4/3. So now we have m and b. All that's left is plugging it in. 

Slope-inctercept: y=mx+b      ------------       y=4/3x+4

 

Hope I helped. Feel free to ask questions.