Raymond B. answered 08/03/21
Math, microeconomics or criminal justice
s(t) =16t^2 + vot
100 = s(.8) = 16(.8)^2 + vo(.8) = 16(.64) + vo(.8)
vo = (100-10.24)/.8 = 89.76/.8 = 112.2
only with an initial velocity of 112.2 feet/sec could you go 100 feet in .8 seconds 112 ft/sec = about 76 mph which seems unusually large for a sky dive jump unless there's some major downwind, maybe a jet stream.
500= s(3.1) = 16(3.1)^2 + 112.2(3.1) = 153.8+ 348 =502
187.5 = s(1.5) = 16(1.5)^2 + 112.2(1.5)= 36 + 168= 204
It's reasonably close. changing wind currents could add to the effects of gravity
3.1 is within 1.6 of 1.5
1.5 is within .7 of .8,
100 is within 100 of 200
500 is within 300 of 200
You would expect the distance after 1.5 seconds to be closer to the distance after .8 seconds 200 is closer to 100 than to 500.