Using the TI-84 calculator, the inverse of the coefficient matrix is calculated to be the matrix
1 5 13
0 -1 -3
1 6 15
Since the inverse exists, the solution to the system is obtained by multiplying the column vector
-4
1
-2
by the inverse matrix above. This results in the column vector
-25
5
-28
So x = -25 y = 5 and z = -28
Notice that the 4- in the problem statement has been changed to -4