v0 = v0x = 100 m/s ; v0y = 0
1) after time t vy = gt = 9.8*0.5 = 4.9 m/s
2) height of th baseball player is ambiguous but height at which the ball is thrown horizontally is calculable
y = gt2/2 = 9.8*(0.5)2/2 = 2.45 m
3) x = v0*t = 100 * (0.5) = 50 m