Find the x and y intercept

(1) 2x+5y=-10

(2) 2x-6y=24

(1) 2x+5y=-10

(2) 2x-6y=24

On the first question ,I got (5,0),(0,-2)

Am I right

Find the x and y intercept

(1) 2x+5y=-10

(2) 2x-6y=24

(1) 2x+5y=-10

(2) 2x-6y=24

On the first question ,I got (5,0),(0,-2)

Am I right

Tutors, please sign in to answer this question.

Paoli, PA

Ma,

Rather than just give you a yes/no let's look at how we can figure it out.

2x+5y=-10

To find the Y intercept what we want to do is figure out what the Y coordinate will be when X=0.

To do this, we can just plug in the X value of 0 and see what we get.

(2)(0) + 5Y = -10

5Y = -10

Y = -10/5

Y = -2

so (0,-2) is correct.

Now, to get the x intercept, we just have to make Y = 0 and solve foe x

2x +(5)(0) = -10

2x = -10

x = -10/2

x = -5

so (-5,0) is also correct.

See if you can use what i showed you here to do the second equation. If you get stuck or confused, just follow up and I will help you further.

Good luck!

Katy, TX

Hi Ma,

1) 2x + 5y = -10

First write it into the standard 'y=mx +c' form (c is always the y intercept)

It will become: 5y = -2x - 10

Now when you simplify this equation you get:

y = -2/5 x -10/5

y = -2/5 x - 2 (this is the final equation where c is -2 = y intercept)

Now for x intercept substitute 0 for y.

5 (0) = -2x -10

0 = -2x -10

0 = -2x -10

2x = -10

x = -5

so the x and y intercepts are -2 and -5 respectively.

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