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If the true value of a quantity is 3.2 and the absolute error must be less than 0.05, find the acceptable measured values.

If the true value is 3.2 and the absolute error must be less than 0.05, find the acceptable measured values.
a) 3.15<x<3.25 b) x<-3.15 0r x>3.25 c) x< 3.15 or x>3.15 d) -3.15<x<3.25

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Ralph L. | Algebra I, II, Visual Basic, Beginning C++ tutorAlgebra I, II, Visual Basic, Beginning C...
4.0 4.0 (1 lesson ratings) (1)
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Check Marked as Best Answer
lower limit: 3.2 - .05 = 3.15
 
upper limit: 3.2 + .05 = 3.25
 
so, 3.15 < x < 3.25
 
 

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Kirill Z. | Physics, math tutor with great knowledge and teaching skillsPhysics, math tutor with great knowledge...
4.9 4.9 (174 lesson ratings) (174)
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The absolute error shows by how much the experimental value differs from the true value. So experimental value may end up greater or smaller than the true value, therefore if the error is 0.05, it means that acceptable values are either smaller or greater than the true value by no more than 0.05. If true value is 3.2, then acceptable values are not smaller than 3.2-0.05=3.15 or not greater than 3.2+0.05=3.25. It can be written as follows:
3.15<x<3.25
 
Thus correct answer is a)