Sun K.
asked 09/08/13Find the general solution?
Find the general solution of x'=(1, 1, 2, 1, 2, 1, 2, 1, 1)x. (this is a 3x3 matrix, 1, 1, 2 on the left, 1, 2, 1 in the middle, 2, 1, 1, on the right, please show your work step by step.)
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1 Expert Answer
Since you didn't give initial values, you are probably supposed to do this problem with eigenvalues.
Let A be your 3x3 matrix. From the characteristic equation det(A-λI)=0 you find the three eigenvalues of A to be λ = -1, 1, and 4. When you substitute these into the equation A-λI=0, you get, up to overall constants the three corresponding eigenvectors x1=[-1,0,1], x2=[1,-2,1], and x3=[1,1,1].
By the theorem from your book, the general solution is therefore
x=c1x1e-t + c2x2et + c3x3e4t.
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Andre W.
09/08/13