(X+5)+40>3x

Question

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. What are the possible values of X for this triangle?

Answer 1

Based on the inequality, we know that the third side is 3x.

 

We solve the inequality as if we were solving an equation.

 

(x + 5) + 40 > 3x

 

x + 45 > 3x

 

 

Subtract x on both sides of the inequality.

 

45 > 2x

 

 

Divide both sides of the inequality by 2.

 

22.5 > x

 

 

This is the same as saying

 

x < 22.5

 

 

So the values of x for this triangle is all numbers less than 22.5