Roman C. answered 08/29/15
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Let S be the length of a side of the equilateral triangle. Drop an altitude from a vertex to split it into two 30-60-90 right triangles. Each has hypotenuse of length S so the short leg has length S/2 and the long leg (the altitude drawn) is (S√3)/2
So the equilateral triangle has area BH/2 = S[(S√3)/2]/2 = (S2√3)/4 which is given as 163 sq. cm.
(S2√3)/4 = 163
(S2√3) = 652
S2 = 652/√3
S = √(652/√3)
The perimeter is 3S which is also the perimeter of the square. So the side of the square is 3S/4 and the diagonal is
D = (√2)(3S/4) = (√2)(3√(652/√3)/4) ≈ 20.58 cm.