Y(s)(s^2+s+5/4)=1/s-e^(-pi*s)/s+s

Tutors, sign in to answer this question.

To solve for Y(s), you would divide by the factor (s²+s+5/4):

Y(s) = ( 1/s-e^(-pi*s)/s+s )/(s²+s+5/4).

I'm assuming there is more to this problem. Your equation looks like the Laplace transform of a differential equation. Are you supposed to find the inverse transform, f(t) ? If so, you would complete the square in the denominator,

s²+s+5/4 = (s+1/2)² + 1,

then split the fraction into three terms, then use standard tables to find the inverse transform.

It's choice C. After dividing s^2+s+5/4 to the other side, how would Y(s) look like?

Y(s) = ( 1/s-e^(-pi*s)/s+s )/(s²+s+5/4)

Already have an account? Log in

By signing up, I agree to Wyzant’s terms of use and privacy policy.

Or

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Your Facebook email address is associated with a Wyzant tutor account. Please use a different email address to create a new student account.

Good news! It looks like you already have an account registered with the email address **you provided**.

It looks like this is your first time here. Welcome!

To present the tutors that are the best fit for you, we’ll need your ZIP code.

Please try again, our system had a problem processing your request.

Alexis G.

All-Subject/Test Prep Tutor, Specializing in Language Instruction

$11.25 per 15 min

View Profile >

Randee S.

Dynamic, versatile tutor for core subject areas K-12

$8.75 per 15 min

View Profile >

Belinda G.

Experienced Elementary School Tutor

$9.75 per 15 min

View Profile >

## Comments

^{-πs/s }+ s, or (b) 1/s - e^{-πs/(s + s)}, or (c) 1/s - e^{-πs}/s + s.