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3(x-2)+2x=5(x-2)-1

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3 Answers

Hello Alli,

   I will have to disagree with the first two comments. The answer to this problem is non-existant. It is an unsolvable problem. Which is why it probably gave you so much trouble.

   Reisa's Steps are right, but her Math was wrong.

    Step One:   Before moving terms across the equation, it is easier to complete the Math on each side. According to PEMDAS, we do parenthesis first.------>>>

3(x-2)+2x=5(x-2)-1-------> 3x-6+2x=5x-10-1

     Combine like terms via addition and subtraction, since there is no exponents, multiplication or division that can be completed at this time.

3x-6+2x=5x-10-1-----> 5x-6=5x-11

      Step Two: Group like terms on different sides of the = sign. (terms with x = numbers). In order to move terms from one side of the equation to the other, you must perform the opposite operation (If a term is being added, you would subtract it and vice versa. If a term is Multiplied, you would Divide and vice versa. A little beyond the scope, but if you are squaring a term (^2), you would take the square root, and vice versa)------->

5x-6=5x-11----> 5x-5x=-11+6.

     From here it is simple math.

5x-5x=-11+6--------> 5x-5x=0 and -11+6= -5 ------> 0=-5  This is simply untrue Zero doesn't equal negative five. Therefore this is False or Unsolvable.

     Please feel free to give me feedback and let me know if this helped.

     For me it is hard to write out words for Math. Haha. Therefore if there is ANYTHING I can or should explain better let me know!

 

       Thanks for taking the time to read and consider : )

Comments

Good job of explaining, Frankie.  Here, have an upvote!  :)

3x-6+2x=5x-10-1 5x-6=5x-11 put the variable on one side by subtracting it and putting the number and x on the left which leaves you with x. Next the -6 is changed to a positive 6 and transfered over to the right side. You end up with equalling -5