Please factorise 4(x-d)^2+(x-d)

Question

Show working please. Thanks so much

Answer 1

4(x-d)²+(x-d)

 =(x-d)[4(x-d)+1]           (taking (x-d) common from both the terms and combining the remaning terms)

 = (x-d)(4x-4d+1)          

                   

Answer 2

4(x-d)² + (x-d)

= (x-d) [4(x-d) + 1]

= (x-d) [4x - (4d-1)]