John K. answered 08/21/15
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Math and Engineering Tutor, Professional Engineer
Choose three points A(4,4),B(6,8),C(4,8) on a graph with origin O(0,0) (O frame), with x the right axis, and y up with positive counterclockwise rotation to form a conventional right hand system. The points can also be considered vectors with associated group properties that we use. A can be translated to O(0,0) by subracting the vector(-4,-4) from the vector(4,4) and then the triangle is A(0,0),B(6,8),C(4,8) in system O. (a). To rotate vectors we can use the Euler transformation matrix with rows[cos(θ),-sin(θ);cos(θ),sin(θ)]} or x′=x*cos(θ)-y*sin(θ), y′=x*sin(θ)+y*sin(θ) or by simply evaluating the new points on the graph in respect to the old using Trigonometry. Now we establish a new coordinate system O¹ with primed origin at B(6,8) in the O frame. They are A¹=(-2,-4),C¹=(2,-4,),B¹=(0,0) in the system with origin at B, called frame O¹. Rotating them 90deg about the origin at B gives the new primed points A²=(4,-2),B²=(0,0),C²=(4,-2) in frame O². We can add the vectors of the O² system to the vector origin of system (O²) measured in the O frame to obtain them in the original system (O frame) or A=(2,-4),B=(6,8),C'(4,2), (b.). To reflect about the x-axis we can use Euler reflection matrix or {[1, 0;0 -1]} about the x-axis. Then x" = x, y"=-y. The reflected verticies (vectors) are A(4,-4),B(6,-8),C(4,-8) (c.) NOTE: You should check this work as I am not noted for accuracy. Math for general rotation groups is fairly involved but this involves nothing but Algebra and Trionometry and can be done with some effort without much Math.