John K. answered 08/10/15
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Math and Engineering Tutor, Professional Engineer
I think the problem is misstated. It should be 9 mi and 6 mi instead of .9 and .6 as these will give negative velocity. Let v be the speed he can swim in still water and t the time for both up and down stream. The current is 1.5. Then the distances he swims are (v+1.5)*t = 9, (v-1.5)*t=6. Equatining the value for t (up = down) gives 9/(v+1.5) = 6/(v-1.5) or
3v = 22.5, v=7.5 or C above. Actually since there are two equations in one unknown one could set t=1 and solve either equation.