
Tom H. answered 08/05/15
Tutor
5
(4)
Tutoring in Middle and High School Subjects
The trick t these things is setting up the problem in equation form and correctly assigning units to the variables.
Team A does 0.25 per hour A = 0.25* aud / hr
Team A + B does 0.40/hr A + B = 0.4 aud / hr
Subtract the first equation from the second equation
A = B = 0.4
A = 0.25
B = 0.4 - 0.25 = 0.15 aud/hr
Now chamge aud/hr to hr/aud aud/hr = 1/0.15 = 6.666...