Bat M.

asked • 08/03/15

Probability Question, Help!

One-hundred students were allowed to re-take an exam for their math course. The probability distribution shows how studying for the latest exam affected their grade when compared with the first time they took the exam. What is the probability that a student who studied for the exam saw an increase in their exam grade? Round to the nearest thousandth.


Exam Grades       |Studied|Did Not Study|Totals
Raise in Grade     |0.52     | 0.06            | 0.58
No Raise in Grade|0.05     | 0.37            | 0.42
Totals                 | 0.57     | 0.43           | 1


A. 0.088

B. 0.897

C. 0.912

D. 0.570
 
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I don't understand how to do this, please help :l

1 Expert Answer

By:

Nicholas J. answered • 08/03/15

Tutor
0 (0)

Duke University PhD; Math, Comp Sci, Econ; 10+ Years Experience

Nicholas J.

The multiple choice answers to this question are tricky, so be careful in this class!
 
0.897 (B) is the probability that a student who saw an increase in their grade had studied (52/58)
0.088 (A) is the probability that a student who studied did Not see an increase in their grade
 
 
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08/03/15

Adam D.

Nicholas,
 
I follow your answer section...
 
Probabilities:
P(raise in grade and studied) = 52/100 = 0.52
P(studied) = 57/100 = 0.57
 
But disagree with your comment section. I get the following...
 
Conditional probability:
P(raise in grade given studied) = P(raise in grade and studied)/P(studied) = (0.52)/(0.57) = 0.912
 
It looks like you conditioned the sample space for a student who saw a raise in grade. Meaning 0.897 is the probability that a student studied for the test given the student saw a raise in grade, that is 52/58. I bet this is just a simple mistake in your comment because the solution built up in your answer portion is right on! Hope this helps.
-Adam
 
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08/09/15

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