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# Find three consecutive integers whose sum is -33

Math questiabout for my high school class in chiolllll

### 3 Answers by Expert Tutors

Jaison N. | A PhD to Teach You Math and PhysicsA PhD to Teach You Math and Physics
4.9 4.9 (150 lesson ratings) (150)
1

Hi omar,

First, lets make sure we know exactly what we need to find. Three consecutive integers, so there are three unknowns. We could start out by saying that each of these integers needs a label: x1, x2, and x3. But the key piece of information here is the word consecutive, meaning following one after the other without interruption. 10 and 11 are consecutive numbers, 11 and 12 are consecutive numbers, and they differ by 1. So, I'll call one integer x and the other two integers x + 1 and x + 2.

The second piece of information is "whose sum is -33". Add them up and set it to -33

x + (x + 1) + (x + 2) = -33

In the last equation, x is the first integer, x + 1 is the next one, and x + 2 is the third integer. Now, combine like terms.

3x + 3 = -33

Subtract 3 from both sides

3x = -36

Divide by 3

x = -12

Adding 1 and 2 gives -11 and -10.

-12 + -11 + -10 = -33.

Kate P. | Science & Math Guru - GRE, ACT, SAT, GED, ASVABScience & Math Guru - GRE, ACT, SAT, GED...
4.9 4.9 (45 lesson ratings) (45)
0

The way to setup this problem is to identify one number, or integer, (the lowest) as x. For consecutive numbers, you add 1, then 2 (and so on). The word "sum" relates to addition. Your three numbers are x, x+1, and x+2.

x + (x+1) + (x+2) = -33

3x + 3 = -33

3x = -36

x = -12; x+1 = -11; x+2 = -10

Check your work: (-12) + (-11) + (-10) = -33

Brad M. | Summer Online Finance Specialist: WACC NPV DCF TVM YTMSummer Online Finance Specialist: WACC ...
4.9 4.9 (233 lesson ratings) (233)
0

Hey Omar -- here's a "kitchen table" approach ... the -33 sum has 3 elements -- what's the average? ... -11 serves as the middle number, with -10 and -12 on each side ... -10,-11,-12.  Best wishes, sir :)