Find the first four terms of the recursively defined sequence

Question

a_1= 256, a_(n+1)= √(a_

Answer 1

Since the problem seems incomplete, I think it might be that a(n+1) = √a(n)

a(1) = 256

a(2) = √a(1) = √256 = 16

a(3) = √a(2) = √16   =  4

a(4) = √a(3) = √4     =  2

 

 

Answer 2

a1 = 256

a2 = √256 = 16

a3 = √16   =  4

a4 = √4     =  2