A function with the roots -2 + 5i and -2 - 5i is:
f(x) = [x - (-2+5i)][x - (-2-5i)]
= [(x-2) - 5i][(x-2) + 5i]
= (x-2)2 - (5i)2 = x2 - 4x + 4 - 25i2
= x2 - 4x + 4 + 25 = x2 - 4x + 29
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If a polynomial function, f(x), has real coefficients and if 6i is a root, then -6i must also be a root.
So, a possible function would be f(x) = [x - 6i][x - (-6i)]
= (x - 6i)(x + 6i)
= x2 - 36i2
= x2 + 36
Arnav M.
07/05/15